Hi,
I modified part of my code.
I tried sending 2 binary files instead of one. The first binary file will always be
corrupted; the second one will be fine. Why? Bug?
:: ************************************
:: Client-Side HTML
:: ************************************
<form name="myForm" action="import.jsp" method="POST" enctype="multipart/form-data">
<input type='hidden' name='dummy' value='dummy'>
<table border="1">
<tr>
<td class='header'>Select Excel File for uploading </td>
<td><input type="file" name="srcfile" size="30"></td>
</tr>
<tr>
<td class='header'>Select Excel File for uploading </td>
<td><input type="file" name="srcfile2" size="30"></td>
</tr>
</table>
<p><input type="button" value="Submit" name="B1" onclick='formSubmit()'> <input
type="reset" value="Reset" name="B2"></p>
</form>
:: ************************************
:: Server-Side JSP
:: ************************************
Iterator iter = list.iterator();
while (iter.hasNext()) {
FileItem fileItem = (FileItem)iter.next();
if (!fileItem.isFormField()) {
String EXCEL_FILENAME = "tmp" + random.nextInt() +".xls";
File resultFile = new File(dir, EXCEL_FILENAME);
fileItem.write(resultFile);
} else {
System.out.println(fileItem.getFieldName() +"-"+fileItem.getString());
}
}
-----Original Message-----
From: Ang Ho Keat
Sent: Tue 6/29/2004 10:52 AM
To: Jakarta Commons Users List
Cc:
Subject: RE: [FileUpload] Corrupted uploaded binary (MS Excel) file
I tried using the inputStream from the fileItem and writing the contents to a
File, but the result is the same - file is still corrupted.
I dont know how to use the inputStream from the request directly as there are
HTML headers in the stream.
-----Original Message-----
From: Schalk [mailto:[EMAIL PROTECTED]
Sent: Mon 6/28/2004 8:20 PM
To: 'Jakarta Commons Users List'
Cc:
Subject: RE: [FileUpload] Corrupted uploaded binary (MS Excel) file
Have you tried reading this in via an input stream and writing out via
an
output stream.
Kind Regards
Schalk Neethling
Web Developer.Designer.Programmer.President
Volume4.Development.Multimedia.Branding
emotionalize.conceptualize.visualize.realize
Tel: +27125468436
Fax: +27125468436
email:[EMAIL PROTECTED]
web: www.volume4.co.za
This message contains information that is considered to be sensitive or
confidential and may not be forwarded or disclosed to any other party
without the permission of the sender. If you received this message in
error,
please notify me immediately so that I can correct and delete the
original
email. Thank you.
:: -----Original Message-----
:: From: Ang Ho Keat [mailto:[EMAIL PROTECTED]
:: Sent: Monday, June 28, 2004 11:08 AM
:: To: [EMAIL PROTECTED]
:: Subject: [Norton AntiSpam] [FileUpload] Corrupted uploaded binary
(MS
Excel) file
::
:: Hi,
::
:: I am able to get a text file to upload successfully but not a binary
(Excel) file.
:: Though the uploading did not report any error, I get an error
message
when I tried
:: to open the uploaded excel file stating that the file is corrupted.
::
:: Any help will be much appreciated. Code snippets are appended
below.
Running on
:: Resin 3.0.8 and win2000 and JDK 1.4.2.
::
:: ************************************
:: Client-Side HTML
:: ************************************
:: <form name='myForm' id='myForm' method="POST" action="import.jsp"
:: enctype="multipart/form-data">
:: <table border="1">
:: <tr>
:: <td class='header'>Select Excel File for uploading </td>
:: <td><input type="file" name="srcfile" size="20"></td>
:: </tr>
:: </table>
:: <p><input type="button" value="Submit" name="B1"
onclick='formSubmit()'>
:: <input type="reset" value="Reset" name="B2"></p>
:: </form>
::
:: ************************************
:: Server-Side JSP
:: ************************************
:: File resultFile = new File(dir, EXCEL_FILENAME);
:: boolean isMultipart = FileUpload.isMultipartContent(request);
:: if (!isMultipart) {
:: throw new Exception("Request is not 'multipart/form-data'.");
:: }
:: DiskFileUpload upload = new DiskFileUpload();
:: upload.setRepositoryPath(dir);
:: List list = upload.parseRequest(request);
:: if (list.size()!=1) {
:: throw new Exception("Please upload only 1 file.");
:: } else if (list.size()==0) {
:: throw new Exception("No file uploaded.");
:: }
:: FileItem fileItem = (FileItem)list.get(0);
:: fileItem.write(resultFile);
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
