Hello,
Here is the sample code:
src/test/Main.java :
package test;
import org.apache.commons.jxpath.JXPathContext;
import org.apache.commons.jxpath.xml.DocumentContainer;
import org.w3c.dom.Element;
import java.io.File;
import java.io.IOException;
import java.util.List;
public class Main {
public static void main(String[] args) throws IOException {
JXPathContext context = JXPathContext.newContext(
new DocumentContainer(new File("test.xml").toURI().toURL())
);
List abcs = context.selectNodes("//abc");
for (Object o : abcs) {
Element el = (Element) o;
System.out.printf("1: %s a=%s%n", el.getNodeName(),
el.getAttribute("a"));
}
JXPathContext subcontext = JXPathContext.newContext(abcs);
List detailedAbcs = subcontext.selectNodes("*");
for (Object o : detailedAbcs) {
Element el = (Element) o;
System.out.printf("2: %s a=%s%n", el.getNodeName(),
el.getAttribute("a"));
}
}
}
test.xml:
<root>
<abc a="1"/>
<abc a="2"/>
<abc a="3"/>
</root>
Result:
1: abc a=1
1: abc a=2
1: abc a=3
The second query "*" resulted in empty sequence. If I query for "/"
instead of "*", I get the three abc elements, but for "/*" result is
empty again. So... how do you think I could get all abc elements where
a=1 from subcontext ?
Thanks,
Yuri.
2007/5/24, Matt Benson <[EMAIL PROTECTED]>:
At first glance it appears this, or something similar,
should be sufficient for what you want to do. Please
assemble some sample code and explain where it is
failing.
Thanks,
Matt
--- Yuri Ushakov <[EMAIL PROTECTED]> wrote:
> Hello.
>
> I can't find a way, yet I think it should be
> possible to do something like this:
>
> JXPathContext subcontext =
>
JXPathContext.newContext(context.selectNodes("//abc"));
>
> So then subcontext would point to a new sequence and
> I could do
> selects on abc elements in it. When I try to do as
> above, I'm simply
> "browsing" a List implementation object... But I
> need to be able to
> execute a query like this:
>
> subcontext.selectNodes("[EMAIL PROTECTED](@b)]");
>
> Where "*" is abc elements selected from first query.
> Any tips?
>
> Thanks,
> Yuri.
>
>
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