Hi Daniel
Thanks for the suggestion. I wanted to exclude the cutline but I found that "
if not ls2.contains(item):" was not always reliable for complex linestrings so
this is what I have done:
from shapely.geometry import LineString
from shapely.ops import cascaded_union
ls1 = LineString([(0,0), (10,10)])
ls2 = LineString([(10,0), (0,10)])
ls2p = ls2.buffer(0.1)
cu = cascaded_union([ls1, ls2])
for item in cu.geoms:
if not item.within(ls2p):
print item
Cheers,
Robert
>>> "Harasty, Daniel J" <dhara...@appcomsci.com> 3/04/2014 2:15 a.m. >>>
Robert,
This will give you all the cut-up parts:
from shapely.geometry import LineString
from shapely.ops import cascaded_union
ls1 = LineString([(0,0), (10,10)])
ls2 = LineString([(10,0), (0,10)])
cu = cascaded_union([ls1, ls2])
print "cut-up lines:"
for item in cu.geoms:
print item
Note that if you consider ls2 the "cut line", and you *don't* want it in the
output, you'll have to do a bit more work:
print "cut-up lines excluding the cut line:"
for item in cu.geoms:
if not ls2.contains(item):
print item
Hope that helps!
DJH
-----Original Message-----
From: community-boun...@lists.gispython.org
[mailto:community-boun...@lists.gispython.org] On Behalf Of Robert Sanson
Sent: Tuesday, April 01, 2014 8:44 PM
To: gispython.org community projects
Subject: [Community] Code for splitting a line with another line
Hi
Does anyone have some Python code for splitting an input line with another
intersecting cut line into two separate lines?
Many thanks,
Robert Sanson
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