Alexey Feldgendler wrote: > On Fri, 29 May 2009 15:49:27 +0200, Ed Kapitein <[email protected]> wrote: > > > >> i need a script/program that will read a crontab line >> ( * * * * * some_action) and output the date and time the job will run. >> >> Does anyone know of such a tool? >> This way i can un-suspend the FR a few seconds prior to the start of >> that cron job. >> >> I already made a script that sort of works, but it is limmited at best >> and i hate to reinvent the wheel again. >> > > You might want to look at this: > http://search.cpan.org/dist/Schedule-Cron >
Hi Alexey and all the others I did take a look at perl, but i am a real perl noob. This is what i have so far: #!/usr/bin/perl use Config::Crontab $event = new Config::Crontab::Event( -data => '*/5 3 * * 5,6 /bin/blech' ); print $event->minute . "\n"; print $event->hour . "\n"; print $event->dom . "\n"; print $event->datetime . "\n"; print $event->command . "\n"; print $event->dump . "\n"; And if i run that i get: */5 3 * */5 3 * * 5,6 /bin/blech */5 3 * * 5,6 /bin/blech Perhaps i am missing the obvious here. Is there someone out there who can make a script that can read a crontab line and give the time and date of the next time it will be executed ? output in the form: secs_since_epoch,yyyy-mm-dd,hh:mm,command would be *great* Many thanks in advance, Ed _______________________________________________ Openmoko community mailing list [email protected] http://lists.openmoko.org/mailman/listinfo/community
