On Dec 20, 2007 10:19 AM, Jason House <[EMAIL PROTECTED]> wrote: > > > On Dec 20, 2007 10:15 AM, Arthur Cater <[EMAIL PROTECTED]> wrote: > > > With 8 hashes per position, the chance of two different boards > > producing a different set of hashes but > > the same canonical hash is greater than 1/2^64, because there will be > > a bias in the choice of canonical > > hashes - toward numerically lower numbers, for instance. > > > > I think. > > > More importantly, how does it differ from 8/2^64 = 1/2^61? >
If you are going to compute all 8 hash keys, you can just add them up at the end instead of picking the minimum. Wouldn't that be better?
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