Hello, 

----- Message d'origine ----
De : Michael Williams <[EMAIL PROTECTED]>
À : computer-go <[email protected]>
Envoyé le : Mercredi, 23 Janvier 2008, 20h38mn 32s
Objet : Re: Re : [computer-go] Bent four in the corner was:Scalability problem 
of play-out policies

ivan dubois wrote:
> I agree that the current implementation of Mogo (from what I know about 
> it)  will not know for sure that the D17 black group is 100% dead.
> It will think that it is X%  dead and stick to that estimation, whatever 
> thinking time you give it. X is a constant that does not depend of 
> thinking time (no scalability).

>How are you arriving at this conclusion?  It makes no sense to me.


Actually this is not true for this exact situation, but I think it is true if 
the black group has enough external liberties.
Suppose it has 10 outside liberties, to make things very clear. 
For the simplicity of my argument, suppose also that the big eye is almost 
entirely filled with white stones (minus 1 liberty) 
Here is my reasoning : 
    Starting from the root, there are some playouts where the black group dies, 
and other where it lives. Let us note X the proportion of playouts that end 
with the black group having been captured.
    Now is there any move A, starting from the root, that will change this 
ratio if you start the random playouts just after A ? I think clearly, the 
answer is no, do you agree with that ? The only relevant possible move would be 
to fill a liberty, but since all liberties will be filled anyway during the 
playouts, this will not change anything to the scenario. The only thing that 
matters is wether or not white plays first at the vital point every time the 
eye is reduced during the playouts.
 Using the same argument, there exists no sequence of less than 8 moves that 
can change the value of X. 
This means all these sequences of liberty filling will be considered to have 
exactly the same value than playing a null move. 
I think it implies that uct will "never" (of course in theory it will at some 
point but I say it would require absurd computing time) find the sequence that 
captures the group with 100% confidence, because this sequence begins with 8 
apparently useless moves.

Ivan


      
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