>I have been unable to find supporting links to show that the higher voltage 
>digital '1' travels faster than the lower voltage digital '0' through copper 
>wire.

Of course you haven't. Everybody should know that the zeros travel faster 
than ones because they are lighter. It is just common sense. :)

Seriously, you should Google on "intersymbol interference." What happens 
when a digital signal (a square wave) travels down a wire is that the 
sharp corners get rounded. This rounding is not symmetrical. The back of 
the pulse drops off quickly, but the front of the pulse has a gentler 
decline. So it looks like the "holes" (the zeros) are being filled in by 
the front of the one pulse. So it looks like the one is catching up with 
the zero.


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