Kaixo!
The "printf" function of bash is supposed to work the same as the C printf()
one; however if you do:
printf "%c\n" 0x40
for example the result won't be at all the same as printf("%c\n",0x40);
I think it is a bug.
What about fixing it like this? :
--- printf.c.orig Tue Apr 6 19:23:53 1999
+++ printf.c Tue Jan 2 21:58:15 2001
@@ -340,7 +340,7 @@
break;
case 'c':
- printf (p, *argument);
+ printf (p, atoi(argument));
break;
case 's':
--
Pablo Saratxaga PGP key 0x8F0E4975
Zerbait gaizki gertatzen ahal balitz, zerbait gertatuko da. -- Murphy
