I think you want to add 6990617 to the @bug tag in RegExTest.
On 12/10/11 01:05 AM, Stephen Flores wrote:
Please review the following webrev (includes new test to demonstrate the bug):
http://cr.openjdk.java.net/~sflores/6990617/
for bug: 6990617 Regular expression doesn't match if unicode character next to
a digit.
A DESCRIPTION OF THE PROBLEM :
Unicode characters are represented as \\+number.
For instance, one could write:
Pattern p = Pattern.compile("\\011some text\\012");
Matcher m = p.matcher("\tsome text\n");
System.out.println(m.find()); // yields "true"
However, if we want to match a string with a digit next to
the unicode character, it doesn't match (whether we "quote"
the regular expression or not). Note the "1" next to the tab
character (unicode 011).
Pattern p = Pattern.compile("\\011\\Q1some text\\E\\012");
Matcher m = p.matcher("\t1some text\n");
System.out.println(m.find()); // yields "false"
This happens because Pattern accepts either \\0011 or \\011 for
the same character. From the javadoc:
\0nn The character with octal value 0nn (0 <= n <= 7)
\0mnn The character with octal value 0mnn (0 <= m <= 3, 0 <= n <= 7)
Evaluation:
Pattern.RemoveQEQuoting() does NOT handle this situation correctly.
The existing implementation now simply copies all ASCII.isAlnum()
characters when handing a quote.
Description of fix:
In the method Pattern.RemoveQEQuoting any ASCII digit at the
beginning of a quote will now be prefixed by "\x3" (not just \
because this would be a backref). 0x30 is the ASCII code for '0'.
Thanks,
Steve.
