On 07/11/13 15:50, Jeff Hain wrote:

One could use that instead, which doesn't have that problem,
and provides values in [0,1-1/2^53], with 1/2^53 granularity:
     public double nextDouble() {
         return (this.nextLong() & ((1L<<53)-1)) * (1.0/(1L<<53));
     }

Thanks very much! We changed to use this approach, which does
indeed seem like the best tradeoff.

-Doug

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