On 07/11/13 15:50, Jeff Hain wrote:
One could use that instead, which doesn't have that problem,
and provides values in [0,1-1/2^53], with 1/2^53 granularity:
public double nextDouble() {
return (this.nextLong() & ((1L<<53)-1)) * (1.0/(1L<<53));
}
Thanks very much! We changed to use this approach, which does indeed seem like the best tradeoff. -Doug
