On Sep 25, 2014, at 13:06, Guy Steele <guy.ste...@oracle.com> wrote:
> (A lurker sticking his nose in here! :-) Is it your intent also to match
> "30s1h" or "20m30m" as a time duration?
>
> If not, you might be better off with a pattern such as
> "((\\d+)h)?((\\d+)m)?((\\d+)s)?" and then the whole problem caused by the
> outer "+" iteration disappear (but you may need to check whether the original
> string was empty).
Yes, this is much better.
>
> But maybe that takes all the fun out of it.
Let someone else enjoy it then. :-)
Thanks
Max
>
> --Guy Steele
>
> On Sep 25, 2014, at 12:51 AM, Wang Weijun <weijun.w...@oracle.com> wrote:
>
>> Hi Sherman
>>
>> I want to match a time duration like "1h20m30s" and "2h". It looks like if I
>> directly use the pattern "((\\d+)([hms]))+", group(2) and group (3) only
>> return the last match (i.e. 30 and s for 1h20m30s). So I tried multiple
>> matching with "(\\d)([hms])" only, but find() does not always match from the
>> beginning, and lookingAt() does not advance after one call.
>>
>> This is my code now;
>>
>> int start = 0;
>> while (true) {
>> if (!m.find() || m.start() != start) {
>> throw new Exception();
>> }
>> start = m.end();
>> print(m.group(1), m.group(2));
>> if (m.hitEnd()) break;
>> }
>> print("Done");
>>
>> Is this the correct way?
>>
>> Thanks
>> Max
>>
>
