Am 17.02.2015 um 11:53 schrieb Andrew Haley:
On 02/17/2015 10:49 AM, Florian Weimer wrote:
That is, the byte array is supplied by the caller, and if we wanted to
use a ByteBuffer, we would have to allocate a fresh one on every
iteration. In this case, neither of the two alternatives you list apply.
I see. So the question could also be whether escape analysis would
notice that a ByteBuffer does not escape. I hope to know that soon.
See:
https://bugs.openjdk.java.net/browse/JDK-6908239
http://bugs.java.com/bugdatabase/view_bug.do?bug_id=6914113
-Ulf
