Hi Tagir,

Nice work. I looked at the implementation and have two comments:

- in Limiter.put:

127         final boolean put(T t) {
 128             int l = limit;
 129             T[] d = data;
 130             if (l == 1) {
131 // limit == 1 is the special case: exactly one least element is stored,
 132                 // no sorting is performed
 133                 if (initial) {
 134                     initial = false;
 135                     size = 1;
 136                 } else if (comparator.compare(t, d[0]) >= 0)
 137                     return false;
 138                 d[0] = t;
 139                 return true;
 140             }
 141             if (initial) {
 142                 if (size == d.length) {
 143                     Arrays.sort(d, comparator);
 144                     initial = false;
 145                     size = l;
 146                     put(t);
 147                 } else {
 148                     d[size++] = t;
 149                 }
 150                 return true;
 151             }
 152             if (size == d.length) {
 153                 sortTail(d, l, size, comparator);
 154                 size = limit;
 155             }
 156             if (comparator.compare(t, d[l - 1]) < 0) {
 157                 d[size++] = t;
 158                 return true;
 159             }
 160             return false;
 161         }


...couldn't the nested call to put in line 146 just be skipped and let the code fall through to "if" in line 152 (with return in line 150 moved between 148 and 149)? This will also fix the return value of put() which is ignored when you make a nested call and replace it with true.

Also, what do you think of the following merging strategy that doesn't need to allocate a temporary array each time you perform a sortTail():

"first" phase:

- accumulate elements data[0] ... data[limit-1] and when reaching limit, sort them and set first = false (this differs from your logic which accumulates up to data.length elements at first and is a better strategy, because it starts the second phase as soon as possible and second phase is more optimal since it already filters elements that accumulates)

"second" phase:

- accumulate elements < data[limit-1] into data[limit] ... data[data.length-1] and when reaching length, sort the tail and perform merge which looks like this: - simulate merge of data[0] ... data[limit-1] with data[limit] ... data[size-1] deriving end indices i and j of each sub-sequence: data[0] ... data[i-1] and data[limit] ... data[j-1]; - move elements data[0] ... data[i-1] to positions data[limit-i] ... data[limit-1] - perform in-place merge of data[limit-i] ... data[limit-1] and data[limit] ... data[j-1] into data[0] ... data[limit-1]


This, I think, results in dividing the additional copying operations by 2 in average and eliminates allocation of temporary array for merging for the cost of pre-merge step which just derives the end indices. There's a chance that this might improve performance because it trades memory writes for reads.

What do you think?

Regards, Peter


On 03/05/2016 06:35 PM, Tagir F. Valeev wrote:
Hello!

One of the popular bulk data operation is to find given number of
least or greatest elements. Currently Stream API provides no dedicated
operation to do this. Of course, it could be implemented by custom
collector and some third-party libraries already provide it. However
it would be quite natural to use existing API:

stream.sorted().limit(k) - k least elements
stream.sorted(Comparator.reverseOrder()).limit(k) - k greatest elements.

In fact people already doing this. Some samples could be found on
GitHub:
https://github.com/search?l=java&q=%22sorted%28%29.limit%28%22&type=Code&utf8=%E2%9C%93

Unfortunately current implementation of such sequence of operations is
suboptimal: first the whole stream content is dumped into intermediate
array, then sorted fully and after that k least elements is selected.
On the other hand it's possible to provide a special implementation
for this particular case which takes O(k) additional memory and in
many cases works significantly faster.

I wrote proof-of-concept implementation, which could be found here:
http://cr.openjdk.java.net/~tvaleev/patches/sortedLimit/webrev/
The implementation switches to new algorithm if limit is less than
1000 which is quite common for such scenario (supporting bigger values
is also possible, but would require more testing). New algorithm
allocates an array of 2*limit elements. When its size is reached, it
sorts the array (using Arrays.sort) and discards the second half.
After that only those elements are accumulated which are less than the
worst element found so far. When array is filled again, the second
half is sorted and merged with the first half.

Here's JMH test with results which covers several input patterns:
http://cr.openjdk.java.net/~tvaleev/patches/sortedLimit/jmh/

You may check summary first:
http://cr.openjdk.java.net/~tvaleev/patches/sortedLimit/jmh/summary.txt
Speedup values bigger than 1 are good.

The most significant regression in the sequential mode of the new
implementation is the ever decreasing input (especially with the low
limit value). Still, it's not that bad (given the fact that old
implementation processes such input very fast). On the other hand, for
random input new implementation could be in order of magnitude faster.
Even for ever ascending input noteable speedup (like 40%) could be
achieved.

For parallel stream the new implementation is almost always faster,
especially if you ignore the cases when parallel stream is
unprofitable.

What do you think about this improvement? Could it be included into
JDK-9? Are there any issues I'm unaware of? I would be really happy to
complete this work if this is supported by JDK team. Current
implementation has no primitive specialization and does not optimize
the sorting out if the input is known to be sorted, but it's not very
hard to add these features as well if you find my idea useful.

With best regards,
Tagir Valeev.


Reply via email to