I have the following as my type of my "value" object. Do I need to implement
readfields and write functions?
private static class StringArrayWritable extends ArrayWritable {
private StringArrayWritable (String [] aSString) {
super (aSString);
}
}
Aaron Kimball-3 wrote:
>
> If you can use an existing serializeable type to hold that field (e.g., if
> it's an integer, then use IntWritable) then you can just get away with
> that.
> If you are specifying your own class for a key or value class, then yes,
> the
> class must implement readFields() and write().
>
> There's no concept of introspection or other "magic" to determine how to
> serialize types by decomposing them into more primitive types - you must
> manually insert the logic for this in every class you use.
>
> - Aaron
>
> On Wed, Jun 3, 2009 at 2:41 PM, dealmaker <vin...@gmail.com> wrote:
>
>>
>> Hi,
>> I have only one field for the record. I wonder if I even need to define
>> a
>> member variable in class Record. Do I even need to implement readfields
>> and
>> write functions if I have only one field? Can I just use the "value"
>> object
>> directly instead of a member variable of value object?
>> Thanks.
>> --
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>> Sent from the Hadoop core-user mailing list archive at Nabble.com.
>>
>>
>
>
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