Whoop, meant to send this reply to the list:

A filter's transfer function simultaneously describes its response to a
> one-sample impulse *and* its response to any complex frequency in the
> z-domain.  There's no need to compromise.
> The reason for this?  Applying a filter to a signal is the same as
> convolving the signal by the filter's impulse response.  Convolution in the
> time domain, as exemplified by filters, is identical to multiplication in
> the frequency domain.  Thus we can look at any point in the transfer
> function (as evaluated in the z-domain) and derive the effect the described
> filter will have on that frequency.


To expand on that:  When we graph the filter response, the transfer
function is what's getting graphed.  A magnitude chart depicts the
logarithm of the transfer function's magnitude for e^(iw) where w is
angular frequency; a phase chart depicts the imaginary part of the
logarithm.

– Evan Balster
creator of imitone <http://imitone.com>

On Tue, Feb 7, 2017 at 10:10 AM, Roman Thilenius <[email protected]>
wrote:

>
>
> isnt that exactly the same as sending a stream of one spike into the
> filter?
>
> i am just not so sure if the transfer function itself really describes the
> "response curve" best. :)
>
>
>
> On Jan 17, 2017, at 6:30 PM, Evan Balster wrote:
>
> I must disagree.  The cleanest way to compute the transfer function, is to
>> compute the transfer function, directly — you'll get an exact answer, with
>> minimal computational expense.
>>
>
>
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