Coreboot fails to identify this cpu correctly, so I hacked
processer_name .c as follows
u32 Test;
Test = cpuid_ebx(0x80000001);
printk_debug("cpuid_ebx %x\n", Test);
BrandId = Test & 0xffff;
Test = cpuid_eax(0x80000001);
printk_debug("cpuid_eax %x\n", Test);
Socket = (Test & 0x00000030) >> 4; // 00b = S1g1, 01b = F
(1207), 11b = AM2
Test = cpuid_ecx(0x80000008);
printk_debug("cpuid_ecx %x\n", Test);
CmpCap = Test & 0x03; // Number of CPU cores
Each core is tested and both return the following.
cpuid_ebx 9a3
cpuid_eax 40f33
cpuid_ecx 1
After a bit of desk checking, either a shift is wrong, or the lookup
value in the following case statement is wrong.
The following hack fixes it
/* Original code commented out, the second shift is increaed by 1
PwrLmt = ((BrandId >> 14) & 0x01) | ((BrandId >> 5) & 0x0e); //
BrandId[8:6,14] */
PwrLmt = ((BrandId >> 14) & 0x01) | ((BrandId >> 6) & 0x0e); //
BrandId[8:6,14]
On the other hand the value in the case statement
case 0x31046:
processor_name_string =
"AMD Athlon(tm) 64 X2 Dual Core Processor
TT00+";
should be 0x3104c
I do not know which
The above module tests each core for number of cores, so this will
always be 1. It treats it as a two CPU machine. Does this make any
difference? The calculation for number of cores could be dropped.
Chris Lingard
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