> >> 20M is indeed to small.
> > My understanding is that 20M is a location, not a size.
> 
> Yes.
> 
> >>  The ramdisk (incl. kernel modules) is on the
> >> order of 26M; I've tried setting it to 32M - this setting is what
> allows
> >> the kernel to actually start; however (as previously mentioned), the
> >> kernel is unable to mount the ramdisk.
> > Because the kernel is looking at 20M and you moved it to 32M?
> 
> No.  These are the parameters passed to the kernel.  What I have seen
> in the past is the ramdisk being loaded close enough to the kernel
> that the kernel stomps it, and corrupts it in early startup.  This should
> be diagnosable by looking at the boot up messages from the kernel startup.

Sorry I misunderstood.  I'm surprised that 16M wasn't enough room to keep
the kernel from overwriting the initrd.

Thanks,
Myles


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