> $ stat -c '%y' file.txt > 2017-07-31 17:50:54.000000000 +0100 > Is there a way to directly print it as 20170731-1750? Thanks.
date --date="@$(stat -c '%Y' file.txt)" '+%+4Y%m%d-%H%M' ________________________________ From: coreutils <coreutils-bounces+williambader=hotmail....@gnu.org> on behalf of Peng Yu <pengyu...@gmail.com> Sent: Monday, March 15, 2021 10:16 PM To: Coreutils <coreutils@gnu.org> Subject: Print modification time in compact form Hi, I see modification time can be printed in this format. $ stat -c '%y' file.txt 2017-07-31 17:50:54.000000000 +0100 Is there a way to directly print it as 20170731-1750? Thanks. -- Regards, Peng
