SZÉPE Viktor writes:

Idézem/Quoting Freddie Witherden <fred...@witherden.org>:

> Hi,
>
> On 05/03/2017 13:03, Sam Varshavchik wrote:
>>> $ g++ -o utest u.c
>>> u.c: In function ‘int main()’:
>>> u.c:5: error: ‘char32_t’ was not declared in this scope
>>> u.c:5: error: expected ‘;’ before ‘c’
>>> u.c:6: error: ‘u32string’ is not a member of ‘std’
>>> u.c:6: error: expected ‘;’ before ‘u’
>>>
>>> $ g++ -std=c++11 -o utest u.c
>>> cc1plus: error: unrecognized command line option "-std=c++11"
>>
>> Ok, so gcc 4.4 is not going to work.
>>
>> According to https://wiki.debian.org/LTS, squeeze has EOLed a year ago.
>>
>>> wheezy with gcc-4.7
>>>
>>> $ g++ -o utest u.c
>>> u.c: In function ‘int main()’:
>>> u.c:5:4: error: ‘char32_t’ was not declared in this scope
>>> u.c:5:13: error: expected ‘;’ before ‘c’
>>> u.c:6:4: error: ‘u32string’ is not a member of ‘std’
>>> u.c:6:19: error: expected ‘;’ before ‘u’
>>>
>>> $ g++ -std=c++11 -o utest u.c
>>> (no output)
>>
>> Ok, so with wheezy, and going forward, you should be ok by explicitly
>> using the -std=c++11 compiler flag.
>>
>> CentOS 5 also comes with gcc 4.4, and CentOS 5 EOLs and the end of this
>> month. But looks like CentOS 6 still uses gcc 4.4, until 2020. That's
>> likely to be problematic, but I'd still like to verify this. It's
>> remotely possible that Red Hat patched in some C++11 support in their
>> build of gcc 4.4.
>
> You can try with -std=c++0x which enables limited support and has been
> available since early 4.x releases.
>

Works on g++ 4.4:

$ g++ -std=c++0x -o utest u.c
(no output)

Ok, so squeeze should be taken care of, and most likely CentOS 5 and 6. Thanks for testing it.

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