SZÉPE Viktor writes:
Idézem/Quoting Freddie Witherden <fred...@witherden.org>:> Hi, > > On 05/03/2017 13:03, Sam Varshavchik wrote: >>> $ g++ -o utest u.c >>> u.c: In function ‘int main()’: >>> u.c:5: error: ‘char32_t’ was not declared in this scope >>> u.c:5: error: expected ‘;’ before ‘c’ >>> u.c:6: error: ‘u32string’ is not a member of ‘std’ >>> u.c:6: error: expected ‘;’ before ‘u’ >>> >>> $ g++ -std=c++11 -o utest u.c >>> cc1plus: error: unrecognized command line option "-std=c++11" >> >> Ok, so gcc 4.4 is not going to work. >> >> According to https://wiki.debian.org/LTS, squeeze has EOLed a year ago. >> >>> wheezy with gcc-4.7 >>> >>> $ g++ -o utest u.c >>> u.c: In function ‘int main()’: >>> u.c:5:4: error: ‘char32_t’ was not declared in this scope >>> u.c:5:13: error: expected ‘;’ before ‘c’ >>> u.c:6:4: error: ‘u32string’ is not a member of ‘std’ >>> u.c:6:19: error: expected ‘;’ before ‘u’ >>> >>> $ g++ -std=c++11 -o utest u.c >>> (no output) >> >> Ok, so with wheezy, and going forward, you should be ok by explicitly >> using the -std=c++11 compiler flag. >> >> CentOS 5 also comes with gcc 4.4, and CentOS 5 EOLs and the end of this >> month. But looks like CentOS 6 still uses gcc 4.4, until 2020. That's >> likely to be problematic, but I'd still like to verify this. It's >> remotely possible that Red Hat patched in some C++11 support in their >> build of gcc 4.4. > > You can try with -std=c++0x which enables limited support and has been > available since early 4.x releases. > Works on g++ 4.4: $ g++ -std=c++0x -o utest u.c (no output)
Ok, so squeeze should be taken care of, and most likely CentOS 5 and 6. Thanks for testing it.
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