Hi anirudh,
Try something like that:
...
.add_property("bar", make_function(&Foo::get_bar,
return_value_policy<reference_existing_object>()) );
....
I think "make_getter" is used to create access to members in the class.
BR
Renato
2008/11/27 anirudh vij <[EMAIL PROTECTED]>:
> Hi,
>
> I've been trying to make the following code work
>
> class Bar{
> public:
> Bar():_int(4){};
> ~Bar(){};
> int get()
> {return _int;}
> private:
> int _int;
> };
>
> class Foo
> {
> public:
> Foo():_bar(Bar()){};
> ~Foo(){};
> Bar& get_bar(){return _bar;}
> private:
> Bar _bar;
> };
>
> #include <boost/python.hpp>
>
> BOOST_PYTHON_MODULE(test)
> {
> using namespace boost::python;
> class_<Bar>("Bar")
> .def("get",&Bar::get)
> ;
> class_<Foo>("Foo")
> .add_property("bar",
> make_getter(&Foo::get_bar,return_value_policy<copy_non_const_reference>())
> )
> ;
> }
>
> The idea is to expose the _bar member via the get() function. I dont want to
> use def_readonly (since this is a dummy test case for a more general problem
> I am facing of using getters with functons returning references)
>
> I get a compile error, with the source of the error in the return value
> policy . The error log is attached.
>
> I also tried return_internal_reference<>(), and
> return_value_policy<return_by_value>, but both give compilation errors.
>
> Any help is appreciated
>
> regards,
> anirudh
>
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>
--
Renato Araujo Oliveira Filho
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