Can you print iptc by it self?
On 03/09/2009, at 3:41 PM, Constant Dupuis wrote:
Ok, thanks,
Now I got a "Segmentation fault" error message when I try "print
iptc['Headline']".
Is the dict object directly exposable ? Or do I have to create a
std::map base class ?
Constant
2009/9/3 Mark Chandler <ad...@lodle.net>:
when you do the exec add the main_namespace twice
object ignored = exec("print('Headline')\n print(iptc['Headline'])
\n",
main_namespace,main_namespace);
On 03/09/2009, at 3:12 PM, Constant Dupuis wrote:
Hi,
I would like to expose a dictionary object instanciated in C++ to a
Python code, which manipulate the dictoinary.
And after extract the resulting modified dictionary back in C++.
I try this :
try {
Py_Initialize();
std::cout << "Hello, World!\n";
dict d;
d["Headline"] = "Titre";
object main_module = import("__main__");
object main_namespace = main_module.attr("__dict__");
main_namespace["iptc"] = ptr(&d);
object ignored = exec("print('Headline')\n"
"print(iptc['Headline'])\n",
main_namespace);
} catch( error_already_set ) {
PyErr_Print();
}
And here is hte output :
Hello, World!
Headline
Traceback (most recent call last):
File "<string>", line 2, in <module>
TypeError: 'NoneType' object is unsubscriptable
What did I missed ?
Thanks en regards,
Constant
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