Troy
Thanks for the prompt reply .. I'm a python expert and a C++ novice ...
Apologies for not getting this ...
I've seen I can define a python mapping using the vector_indexing suite
class_< std::vector< std::vector<double> > >("vector_double2")
.def(vector_indexing_suite<std::vector< std::vector<double> > >
but I can't see how to get that information into the init argument in
the C++
class_<A>("A")
.def(init<vector_double2>( ))
as vector_double2 isn't known when the c++ compiles, so this clearly
isn't the "type" argument to which you refer. Clearly there's something
I'm missing. How do I define a type? Should I be using the named
constructors/factories described in
http://wiki.python.org/moin/boost.python/HowTo? If so how?
Thanks again
Tim
On 06/01/2010 23:16, troy d. straszheim wrote:
Tim Couper wrote:
I'm trying to boost-python a vector-of-vectors, like
class A
{
public
A(const std::vector<std::vector double >>& my_array);
};
and would intuitively write the wrapper:
BOOST_PYTHON_MODULE(foo)
{
using namespace boost::python
class_<A>("A")
.def(init(std::vector<std::vector<double> >())
;
but get the error "a call to a constructor cannot appear in a
constant expression"
Syntax error, init takes a type argument: init<T>()
-t
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