I knew (hoped, really) there would be a simple solution!
Thanks, it works beautifully.
Michael
PS: Sorry, I posted earlier, but didn't notice that I got rejected
because I used the wrong sender address...
On 01/16/2013 10:29 PM, Wojciech Mamrak wrote:
> Hi,
>
> bp::object static_instance()
> {
> static bp::object* result = new bp::object(boost::ref(A::static_a));
> return *result;
> }
>
> Instead of exposing a function static_instance in your module, you can
> alternatively add a variable to your module's scope:
>
> scope sc;
> sc.attr("static_a") = boost::ref(A::static_a); //no copy here
>
> regards
>
>
> 2013/1/16 Michael Wild <them...@users.sourceforge.net>:
>> Dear all
>>
>> I struggle to find a way in which I can wrap a static instance in a
>> bp::object without copying it. The goal is to have object identity for
>> this static instance:
>>
>> struct A {
>> /*...*/
>> static A static_a;
>> };
>>
>> a A::a;
>>
>> bp::object static_instance()
>> {
>> static bp::object* result = new bp::object(A::static_a); // [1]
>> return *result;
>> }
>>
>> Wrapping A and static_instance with Boost.Python is no problem, and
>> everything works as expected, however the A::static_a that is being
>> passed to bp::object() at [1] is being copied, which defeats the whole
>> purpose.
>>
>> Anybody has an idea how achieve this? Thanks!
>>
>> Cheers
>>
>> Michael
>
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