I got an overloaded function:
void f(int n)
{
std::clog << "invoked f(int n = " << n << ")" << std::endl;
}
void f(double d)
{
std::clog << "invoked f(double d = " << d << ")" << std::endl;
}
If I put declarations in that order:
void (*f_int)(int) = &f;
void (*f_double)(double) = &f;
BOOST_PYTHON_MODULE(test)
{
def("f", f_int);
def("f", f_double);
}
No matter what I pass into the function f, f(double) is invoked every time.
Even though I call f(int(1)) I will see "invoked f(double d = 1)".
But if I declare the function f in reversed order:
BOOST_PYTHON_MODULE(test)
{
def("f", f_double);
def("f", f_int);
}
I will see "invoked f(int n = 5)" when I call f(5) and "invoked f(double d =
3.14)" when I call f(3.14) as it has to be. Why does it happen? Why does it
depend on declaration order?
--
Ilya.
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