I got an overloaded function: void f(int n) { std::clog << "invoked f(int n = " << n << ")" << std::endl; }
void f(double d) { std::clog << "invoked f(double d = " << d << ")" << std::endl; } If I put declarations in that order: void (*f_int)(int) = &f; void (*f_double)(double) = &f; BOOST_PYTHON_MODULE(test) { def("f", f_int); def("f", f_double); } No matter what I pass into the function f, f(double) is invoked every time. Even though I call f(int(1)) I will see "invoked f(double d = 1)". But if I declare the function f in reversed order: BOOST_PYTHON_MODULE(test) { def("f", f_double); def("f", f_int); } I will see "invoked f(int n = 5)" when I call f(5) and "invoked f(double d = 3.14)" when I call f(3.14) as it has to be. Why does it happen? Why does it depend on declaration order? -- Ilya. _______________________________________________ Cplusplus-sig mailing list Cplusplus-sig@python.org https://mail.python.org/mailman/listinfo/cplusplus-sig