FYI, you might also like this version: Python 3: ':'.join('%02x' % b for b in s)
Python 2: ':'.join('%02x' % ord(b) for b in s) On Tue, Feb 12, 2019 at 10:29 AM Gilbert Mendoza <gmend...@gmail.com> wrote: > Thank you, Alexander. Your solution is much cleaner. Your Python Kung Fu > is strong. :-) > > hash = ":".join([hex(h)[2:].upper() for h in hash_bytes]) >> print(hash) >> '76:E1:81:9F:AD:F0:6A:55:EF:4B:12:6A:2E:F7:43:C2:BA:E8:A1:51' >> > > Thanks, again! > > Sincerely, > > Gilbert > _______________________________________________ > Cryptography-dev mailing list > Cryptography-dev@python.org > https://mail.python.org/mailman/listinfo/cryptography-dev >
_______________________________________________ Cryptography-dev mailing list Cryptography-dev@python.org https://mail.python.org/mailman/listinfo/cryptography-dev