At 05:14 PM 12/11/2000 -0800, Nikita Borisov wrote: >But in his examples, addition mod 2^128 - 159 can be implemented rather >quickly: > >S_i = S_{i-1} + b [regular 128-bit addition] >if (b > S_i) S_i += 159 Ahhh, yes, a classical example of premature optimisation. This is, of course, a different definition of modular arithmetic than most people would use. Suppose that the result of the addition S_i falls into the range [2^128-159 .. 2^128) then his nice quick method gives an answer that isn't reduced at all, whereas it really ought to be in the range [0 .. 159) by most people's definitions of modular arithmetic. So long as both ends use the broken method, or you aren't terribly unlucky (since only about 1 in 2^121 calculations will hit this case), it will all still work. Greg. Greg Rose INTERNET: [EMAIL PROTECTED] Qualcomm Australia VOICE: +61-2-9181-4851 FAX: +61-2-9181-5470 Level 3, 230 Victoria Road, http://people.qualcomm.com/ggr/ Gladesville NSW 2111 232B EC8F 44C6 C853 D68F E107 E6BF CD2F 1081 A37C
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