[Moderator's Note: Please please don't top post. --Perry]

That paper was from 1980. A few things have changed since then. =)

In any case, my point still stands: what you actually want is some e-cash system with some special properties. Commutative encryption is neither necessary nor (probably) sufficient for what you want. Have you at least looked at the literature (which must be well over 100 papers) on e-cash?

On Mon, 22 Mar 2010, Sergio Lerner wrote:

Commutativity is a beautiful and powerful property. See "On the power of Commutativity in Cryptography" by Adi Shamir. Semantic security is great and has given a new provable sense of security, but commutative building blocks can be combined to build the strangest protocols without going into deep mathematics, are better suited for teaching crypto and for high-level protocol design. They are like the "Lego" blocks of cryptography!

Now I'm working on an new untraceable e-cash protocol which has some additional properties. And I'm searching for a secure commutable signing primitive.

Best regards,
Sergio Lerner.

On 22/03/2010 09:56 a.m., Jonathan Katz wrote:
Sounds like a bad idea -- at a minimum, your encryption will be deterministic.

What are you actually trying to achieve? Usually once you understand that, you can find a protocol solving your problem already in the crypto literature.

On Sun, 21 Mar 2010, Sergio Lerner wrote:

I looking for a public-key cryptosystem that allows commutation of the operations of encription/decryption for different users keys
( Ek(Es(m)) =  Es(Ek(m)) ).
I haven't found a simple cryptosystem in Zp or Z/nZ.

I think the solution may be something like the RSA analogs in elliptic curves. Maybe a scheme that allows the use of a common modulus for all users (RSA does not). I've read on some factoring-based cryptosystem (like Meyer-Muller or Koyama-Maurer-Okamoto-Vantone) but the cryptosystem authors say nothing about the possibility of using a common modulus, neither for good nor for bad.

Anyone has a deeper knowledge on this crypto to help me?

Best regards,
Sergio Lerner.
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