Thanks david !!.. On Sep 19, 1:59 pm, David Irvine <[email protected]> wrote: > Very quickly (you may need to fix code) (first way) > > SHA256 hash; > > string message1="Hello"; > string message2 = "world"; > > byte digest[SHA256::DIGESTSIZE * 2]; > > hash.CalculateDigest(digest, (byte*) > message1.c_str(),message1.length()); > hash.CalculateDigest(&digest[SHA256::DIGESTSIZE], > (byte*)message2.c_str(),message2.length()); > > Sorry running now :-( > David > > On Mon, Sep 19, 2011 at 9:54 PM, shinde <[email protected]> wrote: > > It would be really helpful if you could give me an example for this. > > > Nitin > > > On Sep 19, 1:48 pm, David Irvine <[email protected]> wrote: > > > One way is to create a byte array that's 2* DIGESTSIZE and then pass > > address > > > of the starting point to the Digest function (&bytearray[0] and > > > &bytearray[digestsize]). In your code you should probably specifically > > > use the correct array size as well (SHA265::DIGESTSIZE). > > > > You could use a stringsink if you are heading that way and then > > > just concatenate the 2 strings. This is potentially easier. There are > > > several examples in the docs for this. > > > > Sorry for quick reply, on way out. > > > > On Mon, Sep 19, 2011 at 9:37 PM, shinde <[email protected]> wrote: > > > > Hello everyone, > > > > > I'm currently working on a requirement which suggests concatenating > > > > two hashes( appending one hash to the other), say hash1 and hash2. > > > > > How can this be achieved using crypto++ ?? > > > > > E.g: > > > > > SHA256 hash; > > > > SHA256 hash2; > > > > string message1="Hello"; > > > > string message2 = "world"; > > > > > byte digest1[SHA::DIGESTSIZE]; > > > > byte digest2[SHA::DIGESTSIZE]; > > > > > hash.CalculateDigest(digest1,(byte*) > > > > message1.c_str(),message1.length()); > > > > hash2.CalculateDigest(digest2, > > > > (byte*)message2.c_str(),message2.length()); > > > > > // Need to concatenate hash and hash2, i.e. hash2 should be appended > > > > to hash1. > > > > > Looking for some help regarding this !!.. > > > > > Thanks, > > > > > Nitin > > > > > -- > > > > You received this message because you are subscribed to the "Crypto++ > > > > Users" Google Group. > > > > To unsubscribe, send an email to > > > > [email protected]. > > > > More information about Crypto++ and this group is available at > > > >http://www.cryptopp.com. > > > -- > > You received this message because you are subscribed to the "Crypto++ > > Users" Google Group. > > To unsubscribe, send an email to > > [email protected]. > > More information about Crypto++ and this group is available at > >http://www.cryptopp.com.
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