@David Nice! Stored that somewhere...
 
degski
 

On Sunday, September 16, 2012 1:35:18 PM UTC+3, David Irvine wrote:

> Here is an XOR filter if you wish to use xor in a transformation chain. 
>
> const size_t kPadSize(YOURPADSIZEHERE);
>
> class XORFilter : public CryptoPP::Bufferless<CryptoPP::Filter> {
>  public:
>   XORFilter(CryptoPP::BufferedTransformation *attachment,
>             byte *pad,
>             const size_t &pad_size = kPadSize)
>       : pad_(pad), count_(0), kPadSize_(pad_size) {
>     CryptoPP::Filter::Detach(attachment);
>   }
>   size_t Put2(const byte* in_string,
>               size_t length,
>               int message_end,
>               bool blocking) {
>     if (length == 0) {
>       return AttachedTransformation()->Put2(in_string, length, message_end,
>                                             blocking);
>     }
>     boost::scoped_array<byte> buffer(new byte[length]);
>
>     size_t i(0);
>     for (; i != length; ++i) {
>       buffer[i] = in_string[i] ^ pad_[count_ % kPadSize_];
>       ++count_;
>     }
>
>     return AttachedTransformation()->Put2(buffer.get(), length, message_end,
>                                           blocking);
>   }
>   bool IsolatedFlush(bool, bool) { return false; }
>
>  private:
>   XORFilter &operator = (const XORFilter&);
>   XORFilter(const XORFilter&);
>   byte *pad_;
>   size_t count_;
>   const size_t kPadSize_;
> };
>
> Best Regards
> David Irvine
>
>
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>
>
> On Sun, Sep 16, 2012 at 11:30 AM, degski <[email protected] 
> <javascript:>>wrote:
>
>> Hi Shahram,
>>  
>> This might not be what you mean, but the xor function is C/C++ is like:
>>  
>> int x = 6544654, y = 9684296;
>>  
>> x ^= y;
>>  
>>  
>> x now contains the xored value of x with y. For your strings, just do it 
>> byte by byte.
>>  
>> Cheers,
>>  
>>  
>> degski
>>
>>  
>> On 16 September 2012 12:21, Shahram <[email protected] <javascript:>>wrote:
>>
>>> "Dear Jay Jay
>>>
>>> Thanks for your quick reply. But What I want is close to what you 
>>> suggest. That's part of an SIP protocol with a "SHA256" hash function. I 
>>> couldn't find XOR function in Crypto++ with the specification that I've 
>>> mentioned before. Is it possible for you to help me in this way? Thanks 
>>> again.  
>>>
>>> On Sunday, September 16, 2012 12:00:02 AM UTC-7, Jay Jay wrote:
>>>>
>>>> I take it you want to encrypt a username with a password. Why roll your 
>>>> own? DefaultEncryptorWithMAC will do this for you:
>>>>
>>>> Use like:
>>>>
>>>> template < typename F >
>>>> const string EncryptString ( const string& instr, const string& 
>>>> passPhrase ) {
>>>>
>>>>     string outstr;
>>>>
>>>>     try {
>>>>
>>>>         DefaultEncryptorWithMAC Encryptor ( passPhrase.c_str ( ), new F 
>>>> ( new StringSink ( outstr ), false ) );
>>>>         Encryptor.Put ( ( byte* ) instr.c_str ( ), instr.size ( ) );
>>>>         Encryptor.MessageEnd ( );
>>>>     }
>>>>       
>>>>     catch ( std::exception& e ) {
>>>>
>>>>         cout << e.what ( ) << endl;
>>>>
>>>>         exit ( 0 );
>>>>     }
>>>>
>>>>     return outstr;
>>>> }
>>>>
>>>> Where F is either HexEncoder or Base64Encoder.
>>>>
>>>> So call 
>>>>
>>>> const string encrypted_username (  EncryptString<Base64Encoder> ( 
>>>> username, password ) );
>>>>
>>>> Cheers,
>>>>
>>>>
>>>> degski 
>>>>
>>>> On 16 September 2012 09:21, Shahram <[email protected]> wrote:
>>>>
>>>>> Dear All
>>>>>
>>>>> Would you please help me to know how can I have a function with the 
>>>>> following specification:
>>>>>
>>>>> Inputs: string  username, password;
>>>>> output string   F(username, password) = username XOR hash (password) 
>>>>>  where hash= SHA256 or anything else.
>>>>>
>>>>> And I need also to have and write the output down in hex . Thanks in 
>>>>> advance.
>>>>>
>>>>> Regards
>>>>> Shahram                     
>>>>>
>>>>> -- 
>>>>> You received this message because you are subscribed to the "Crypto++ 
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>>>>> To unsubscribe, send an email to cryptopp-user...@**googlegroups.com.
>>>>> More information about Crypto++ and this group is available at 
>>>>> http://www.cryptopp.com.
>>>>
>>>>
>>>>
>>>>
>>>> -- 
>>>> "When I see a bird that walks like a duck and swims like a duck and 
>>>> quacks like a duck, I call that bird a duck."
>>>>  
>>>> - *James Whitcomb Riley*
>>>>
>>>>  -- 
>>> You received this message because you are subscribed to the "Crypto++ 
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>>> To unsubscribe, send an email to 
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>>
>>
>>
>>
>> -- 
>> "When I see a bird that walks like a duck and swims like a duck and 
>> quacks like a duck, I call that bird a duck."
>>  
>> - *James Whitcomb Riley*
>>
>>  -- 
>> You received this message because you are subscribed to the "Crypto++ 
>> Users" Google Group.
>> To unsubscribe, send an email to 
>> [email protected]<javascript:>
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>>
>
>

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