I don't know if this is a possible scenario, but is it possible to have a boot
type partition that is not marked as bootable ?
For example, suppose we have this type of configuration:
sfdisk_info_dos = {
"label": "dos",
"id": "0xb0dbdde1",
"device": "/dev/vdb",
"unit": "sectors",
"partitions": [
{"node": "/dev/vdb1", "start": 2048, "size": 8388608,
"type": "80"},
{"node": "/dev/vdb2", "start": 8390656, "size": 8388608,
"type": "83"}]
}
In that scenario the boot check would fail, because we will not have the
bootable key, but the MBR_TYPE_TO_CURTIN_MAP would find the expected "boot"
flag as we want.
But do we want to have a boot partition that is not marked as bootable ? I
think this scenario can happen if we provide a custom sfdisk_info dict to the
function, but I don't know if that can actually happen, or if it does, if it is
a problem.
--
https://code.launchpad.net/~raharper/curtin/+git/curtin/+merge/384133
Your team curtin developers is requested to review the proposed merge of
~raharper/curtin:fix/partition-verify-flags-msdos-primary-types into
curtin:master.
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