I dug through the src to figure out just this. Looks like if you have your id "myServiceImpl" - provide an implementor="#myServiceImpl" instead of the class name.
See org/apache/cxf/jaxws/spring/EndpointDefinitionParser.java#111 -Brice On 5/23/07, Marcelo Fernandes <[EMAIL PROTECTED]> wrote:
Hi all, First of all, congratulations for cxf. It fits perfect to my project! Using the tutorial, I saw the way to declare server beans:<beans xmlns="http://www.springframework.org/schema/beans"; xmlns:xsi=" http://www.w3.org/2001/XMLSchema-instance"; xmlns:jaxws=" http://cxf.apache.org/jaxws"; xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsdhttp://cxf.apache.org/jaxws http://cxf.apache.org/schema/jaxws.xsd";> <import resource="classpath:META-INF/cxf/cxf.xml" /> <import resource="classpath:META-INF/cxf/cxf-extension-soap.xml" /> <import resource="classpath:META-INF/cxf/cxf-servlet.xml" /> <jaxws:endpoint id="helloWorld" implementor=" demo.spring.HelloWorldImpl" address="/HelloWorld" /> </beans> How can I change the implementor tag in <javaws:endpoint> to use the id of declared bean at spring config file instead of a class impl name? Thanks in advance,marcelo _________________________________________________________________ Obtenha o novo Windows Live Messenger! http://get.live.com/messenger/overview
-- Brice Ruth Software Engineer, Madison WI
