Thanks Dan.
But when I implement as shown below.
MyThing implementor = new MyThingImpl();
String address = "http://localhost:8080/MyThingInstance";
javax.xml.ws.Endpoint jaxwsEndpoint = Endpoint.publish(address,
implementor);
MyThing implementor2 = new MyThingImpl();
String address2 = "http://localhost:8080/MyThingInstance2";
javax.xml.ws.Endpoint jaxwsEndpoint = Endpoint.publish(address2,
implementor2);
I tried to access http://localhost:8080/MyThingInstance?wsdl and
http://localhost:8080/MyThingInstance2?wsdl. Both the WSDL has the same
service definition.
I do not see MyThingInstance2 anywhere in the WSDL.
Am I missing something?
Best regards
Arul
Daniel Kulp wrote:
On Wednesday 09 April 2008, Arul Dhesiaseelan wrote:
Daniel Kulp wrote:
On Wednesday 09 April 2008, Benson Margulies wrote:
A bit of googling got me nowhere here.
I want to publish a service on both a http: address and a local:
address. Two jaxws:endpoints? Can they point to the same
#implementation bean?
Yep. It's the same as if you did:
MyThing thing = new MyThingImpl();
Endpoint.publish(address1, thing);
Endpoint.publish(address2, thing);
Dan,
Does this work?
MyThing thing1 = new MyThingImpl();
MyThing thing2 = new MyThingImpl();
Endpoint.publish(address1, thing1);
Endpoint.publish(address2, thing2);
When I invoke the service at address1, it should invoke thing1 and
address2 should invoke thing2.
Thanks!
Arul
Yep. That's exactly how it's supposed to work.
