Hi.
I've a question regarding job control in cygwin bash.
Below is a simple program that prints out the process id of itself.
C:\builds>cat a.c
#include <stdio.h>
#include <process.h>
int main(int argc, char ** argv)
{
printf("pid=%d\n", _getpid());
return 0;
}
Compiling and running it in foreground from cygwin bash works as expected:
user@host /cygdrive/c/builds
$ cl a.c
Microsoft (R) C/C++ Optimizing Compiler Version 19.44.35217 for x86
Copyright (C) Microsoft Corporation. All rights reserved.
a.c
Microsoft (R) Incremental Linker Version 14.44.35217.0
Copyright (C) Microsoft Corporation. All rights reserved.
/out:a.exe
a.obj
user@host /cygdrive/c/builds
$ ./a
pid=2352
However, if I start it in background and attempt to get back the pid
of the started process via $!, the result is not what one would
expect. The actual process pid printed out from my program differs
from what cygwin bash thinks is "process ID of the job most recently
placed into the background".
user@host /cygdrive/c/builds
$ ./a &
[1] 15909
user@host /cygdrive/c/builds
$ pid=27008
echo $!
15909
[1]+ Done ./a
So my question is - is this a cygwin bash quirk (i.e. the fact that $!
is not the pid of the started process) caused by how fork/process
startup is implemented in cygwin? I have tried reading
https://cygwin.com/cygwin-ug-net/highlights.html#ov-hi-process but
could not see anything relevant aside from "Job control works as
expected in shells that support it." in the Signals section. Is there
any way to get the actual process pid?
Many thanks in advance,
Vadym
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