I have a habit of keeping cygwin packages on my computer and updating them from time to time using setup.exe. This saves me time when I need to install on another computer.
This creates a problem of old versions of packages accumulating in my download directory. I used to remove them by hand but that is a time consuming process. Finally I wrote an awk script to help me deal with the problem. And just for kicks I added a shell wrapper :).
Attached are the scripts. I hope they could be useful to someone else. I am sure they can be improved but they have been useful to me as is.
Thanks, Alex
#! /bin/awk
BEGIN { \
last_pkg = "";
last_date = 0;
last_dir = "";
last_pkg_name = "";
cmd = "find release -type f -printf '%h %f %TY%Tm%Td\n'";
while(( cmd | getline ) > 0)
{
dir = $1;
pkg = $2;
date = $3;
count = split(dir, part, "/");
if( last_pkg_name == part[count] ){
if( date < last_date ){
print dir "/" pkg;
continue;
}else{
print last_dir "/" last_pkg;
}
}
last_pkg = pkg;
last_date = date;
last_dir = dir;
last_pkg_name = part[count];
}
close(cmd);
}
#! /bin/bash
# Version of cyg-remove-dups in bash, just for kicks. Still uses awk and find
# awk is used in a normal way. Trick is to pass program to it with the data
# on stdin.
find release -type f -printf "%h %f %TY%Tm%Td\n" | \
awk -- '
BEGIN { \
last_pkg = "";
last_date = 0;
last_dir = "";
last_pkg_name = "";
}
{
dir = $1;
pkg = $2;
date = $3;
count = split(dir, part, "/");
if( last_pkg_name == part[count] ){
if( date < last_date ){
print dir "/" pkg;
next;
}else{
print last_dir "/" last_pkg;
}
}
last_pkg = pkg;
last_date = date;
last_dir = dir;
last_pkg_name = part[count];
}
'
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