On 10/31/2005, Siegfried Heintze wrote:
>As someone mentioned, you can use "cygpath -p" to convert a POSIX-style >> path into a Win32-style one.I think I need to go the other way. Given a CLASSPATH variable in windows, how do I convert it to cygwin? Do I use ":" to separate the elements, or do I use "\;". If I use ":", what about the windows device names? It seems to me this should have worked, but it does not: * CLASSPATH=.\;c:\\dev\\xalan\\xalan-j_2_7_0\\xsltcservlet.jar\;others * export $CLASSPATH * echo ${CLASSPATH} * javac myprogram.java
If you're running from bash or any other Cygwin shell, then the path is already in POSIX form. 'javac' won't understand this, since it is a Windows program. 'cygpath' is the way to convert between POSIX paths and Windows/DOS, forward and back. In your case, you want POSIX->Windows/DOS conversion. See 'man cygpath' for more details. -- Larry Hall http://www.rfk.com RFK Partners, Inc. (508) 893-9779 - RFK Office 838 Washington Street (508) 893-9889 - FAX Holliston, MA 01746 -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
