freq[k] = sum_over_n(time[n] * exp(-2 * pi * i * k * n / N) time[n] = 1/N * sum_over_k(freq[k] * exp(2 * pi * i * k * n / N)
yay sums could be transformed to array operations
Undescribed Horrific Abuse, One Victim & Survivor of Many Thu, 10 Nov 2022 08:43:31 -0800
freq[k] = sum_over_n(time[n] * exp(-2 * pi * i * k * n / N) time[n] = 1/N * sum_over_k(freq[k] * exp(2 * pi * i * k * n / N)
yay sums could be transformed to array operations