Chris Colbert skrev:
> and within that loop it is these statements that take the bulk of the time:
>
> F = ((f1**2)**(1/e2) + (f2**2)**(1/e2))**(e2/e1) + (f3**2)**(1/e1)
>
> temperr = (C4 * (F**(e1) - 1))**2
>
> and replacing the powers with serial multiplications don't really help any...
>
Does this help?
cdef extern from "math.h":
double pow(double, double)
F = pow(pow((f1*f1),(1/e2)) + pow((f2*f2),(1/e2)),(e2/e1)) \
+ pow((f3*f3),(1/e1))
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