On Jul 21, 2010, at 7:49 PM, Bronwyn Woods wrote:
> I'm working with an App Wizard application. I have a grid on form A that
> lists some of the records associated with form B. When the user clicks on a
> grid row, I would like to open or switch focus to form B's edit page for
> that record. By using the show() method as done for the file-open menu, I
> can successfully open the appropriate form. However, I have two questions.
>
> 1. If I click on a row twice, form B opens twice. If a form is already
> open, is it possible to just switch focus to that form instead of opening it
> again? I've tried a few of the dForm properties that looked like they might
> be appropriate but have had no luck.
I would store a reference to form B on form A, and try to use that if
possible. The code to show form B would look something like:
try:
self.formB.show()
except AttributeError:
self.formB = MyFormBClass()
self.formB.show()
Additionally, I would add buttons to dismiss form B that only call
self.hide() instead of self.release(); this way the next time the form is
needed, the same form can be re-used.
> 2. How to I tell form B to show the edit screen for the record selected in
> form A (instead of the default grid page)?
I'm guessing from your description that both forms A&B are
AppWizard-generated forms. This is when AppWizard starts to lose its advantage,
as it wasn't designed to work the way you're trying to make it work, and as a
result you're going to have to spend some time coding around the intended
design. I'd change the code above to look more like this:
try:
self.formB.pageFrame.SelectedPageNumber = 2
except AttributeError:
self.formB = MyFormBClass()
self.formB.pageFrame.SelectedPageNumber = 2
self.formB.update()
self.formB.show()
This will set the selected page to the edit page, update its controls
with the current bizobj record, and then show the form.
I hope this helps!
-- Ed Leafe
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