On Tuesday, November 09, 2010 12:49:19 pm Paul McNett wrote:
> On 11/9/10 7:32 AM, John Fabiani wrote:
> > I was wondering if it was intended that the getDateFromString() method
> > not accept a four digit year in a string?
> >
> > daboDate.getDateFromString('06/19/66')
> > datetime.date(2066, 6, 19)
> >
> > daboDate.getDateFromString('06/19/1966')
>
> getDateFromString() by default only converts dates in 2 formats. It'll try
> them in this order:
>
> ISO8601 ("YYYY-MM-DD")
> %x (the current locale's date format)
>
> What's happening to you is that the current locale's format must be
> %m/%d/%y (MM/DD/YY) but you are passing the 4-digit year and python's
> time.strftime() function can't convert it.
>
> Paul
I believe the dabo format is "%m/%d/%Y". Unless it's being set somewhere
else?
So you are saying that somewhere the dabo format is " %m/%d/%y" and that's the
root cause - right?
I fixed it by using the following:
datetime.datetime(*time.strptime(return_to_court_date, "%m/%d/%Y")[0:5])
But I was very surprised to see the dabo method fail.
Johnf
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