* Kevin Korb <[email protected]> [12.11.2015 08:52]:
> $ echo -n testing
> - -n testing
in POSIX the '-n' switch (and -e) is undefined.
you can work around this via hijacking the call:
#!/bin/sh
echo()
{
case "$1" in
'-n')
shift
printf '%s' "$@"
;;
*)
printf '%s\n' "$@"
;;
esac
}
echo foo
echo -n bar
if you really want to remove all the bashisms, it
can be a lot of work. dont blame dash for this, but
the script author. also consider using shellsheck.net
for this with the correct shebang.
bye, bastian
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