By the way, this works as I would expect with data.frame on the same environment:
> df1 = data.frame(a=character()) > df2 = data.frame(a=character()) > df1 [1] a <0 rows> (or row.names with length 0) > df2 [1] a <0 rows> (or row.names with length 0) > rbind(df1, df2) [1] a <0 rows> (or row.names with length 0)
-- Alexandre Sieira
CISA, CISSP, ISO 27001 Lead Auditor
"The truth is rarely pure and never simple."
Oscar Wilde, The Importance of Being Earnest, 1895, Act I
On 30 de setembro de 2013 at 13:01:47, Alexandre Sieira ([email protected]) wrote: I encountered the following behavior with data.table 1.8.10 on R 3.0.2 on Mac OS X and was wondering if that is expected:
> dt1 = data.table(a=character()) > dt2 = data.table(a=character()) > dt1 Empty data.table (0 rows) of 1 col: a > colnames(dt1) [1] "a" > dt2 Empty data.table (0 rows) of 1 col: a > colnames(dt2) [1] "a" > rbind(dt1, dt2) Error in setnames(ret, nm.original) : x has no column names
Enter a frame number, or 0 to exit
1: rbind(dt1, dt2) 2: rbind(deparse.level, ...) 3: data.table::.rbind.data.table(...) 4: setnames(ret, nm.original)
If I rbind two zero-row data.table objects with matching column names, I would have expected to get a zero-row data.table back (0 + 0 = 0, after all). -- Alexandre Sieira
CISA, CISSP, ISO 27001 Lead Auditor
"The truth is rarely pure and never simple."
Oscar Wilde, The Importance of Being Earnest, 1895, Act I
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