Nicely reproducible post. Reproducible in v1.9.3 (latest commit) as well.

This is a tricky one. It happens because you’re setting key on .SD which should 
normally not be allowed. What happens is, when you set key the first time, 
there’s no key set (here) and therefore key is set on all the columns x1, x2 
and x3.

Now, the next group (in the by=.) is passed to your function, it’ll have the 
key already set to x1,x2,x3 (because setkey modifies the object by reference), 
but .SD has obtained new data corresponding to this group. And data.table sorts 
this data, knowing that it already has key set.. but if the key is set then the 
order must be 1:n. But it wouldn’t be, as this data isn’t sorted. data.table 
warns in those scenarios.. and that’s why you get the warning.

To verify this, you can try:

conflictsTable1 <- function(f, address) {
  u <- unique(setkey(f))
  setattr(f, 'sorted', NULL)
  if (nrow(u) == 1) return(NULL)
  u
}
Basically, we set the key of f (which is equal to .SD as it’s only modified by 
reference) to NULL everytime after.. so that .SD for the new group will not 
have the key set.

The ideal scenario here, IIUC, is that setkey(.SD) or things pointing to .SD 
should not be possible (locking binding doesn’t seem to affect things done by 
reference..). .SD however should retain the key of the data.table, if a key was 
set, wherever possible.


Arun

From: Ron Hylton [email protected]
Reply: Ron Hylton [email protected]
Date: June 14, 2014 at 1:55:53 AM
To: [email protected] 
[email protected]
Subject:  [datatable-help] data.table is asking for help  

The code below generates the warning:

 

In setkeyv(x, cols, verbose = verbose) :

  Already keyed by this key but had invalid row order, key rebuilt. If you 
didn't go under the hood please let datatable-help know so the root cause can 
be fixed.

 

This is my first attempt at using datatable so I probably did something dumb, 
but maybe that‘s useful for someone.  The first case is the one that gives the 
warnings.

 

I’m also surprised at the timings.  I wrote the original algorithm using 
dataframe & ddply and I expected datatable to be substantially faster; the 
opposite is true.

 

The algorithm does the following:  Certain columns in the table are keys and 
others are values in the sense that each row with the same set of keys should 
have the same set of values.  Find all the key sets for which this is not true 
and return the keys sets + conflicting value sets.

 

Insight into the performance would be appreciated.

 

Regards,

Ron

 

library(data.table)

library(plyr)

 

conflictsTable1 <- function(f) {

  u <- unique(setkey(f))

  if (nrow(u) == 1) return(NULL)

  u

}

 

conflictsTable2 <- function(f) {

  u <- unique(f)

  if (nrow(u) == 1) return(NULL)

  u

}

 

conflictsFrame <- function(f) {

  u <- unique(f)

  if (nrow(u) == 1) return(NULL)

  u

}

 

N <- 10000

test <- data.table(id=as.character(10000*sample(1:N,N,replace=TRUE)), 
x1=rnorm(N), x2=rnorm(N), x3=rnorm(N))

 

setkey(test,id)

 

print(system.time(ut1 <- test[, conflictsTable1(.SD), by=id]))

 

print(system.time(ut2 <- test[, conflictsTable2(.SD), by=id]))

 

print(system.time(uf <- ddply(test, .(id), conflictsFrame)))

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