Is this what you want:
> require(data.table)
> DT <- data.table(id=c(1,1,4,4,4),
+
+
date=as.character(c("1997-04-26","missing","1998-08-25","missing","1998-11-07")))
> DT
id date
1: 1 1997-04-26
2: 1 missing
3: 4 1998-08-25
4: 4 missing
5: 4 1998-11-07
> DT[date == "missing", date := '2002-06-30']
> DT
id date
1: 1 1997-04-26
2: 1 2002-06-30
3: 4 1998-08-25
4: 4 2002-06-30
5: 4 1998-11-07
>
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Tue, Jul 29, 2014 at 12:28 PM, Frank S. <[email protected]> wrote:
> Hi everyone,
>
>
>
> I would want to replace only the "missing" characters in date column by
> "2002-06-30" character (I will make the change to date format in future):
>
>
>
> DT <- data.table(id=c(1,1,4,4,4),
>
>
> date=as.character(c("1997-04-26","missing","1998-08-25","missing","1998-11-07")))
> DT
>
>
>
> id date
> 1: 1 1997-04-26
> 2: 1 NA
> 3: 4 1998-08-25
> 4: 4 NA
> 5: 4 1998-11-07
>
>
>
>
>
> DT[,list(id, date=if(variable==NA) {"2002-06-30"} else date)]
>
>
>
> But I get an error message.
>
>
>
> Is it posible to do it under data table format?
>
>
>
> Many thanks to all the data.table help members!!
>
>
> _______________________________________________
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