Q. How do I work out how many hours have been worked from a timesheet?
This solution takes a file in the format ISO-Date, WhiteSpace, Name
It does not take into account people who forget to log in or out apart from making sure there's an even number of dates for each user.
[Note: this later could be partly solved by splitting into days and then checking for an even number of times. Flagging days for which data was not calculable]
#!/usr/bin/perl
use strict; use warnings; use DateTime; use DateTime::Span; use DateTime::SpanSet; use DateTime::Format::Duration; use DateTime::Format::ISO8601; my $ISO = DateTime::Format::ISO8601->new(); my $DURATION = DateTime::Format::Duration->new( pattern => '%Y years, %m months, %e days, %H hours, %M minutes, %S seconds', normalize => 1, ); my %users; foreach (<DATA>) { chomp; my ($dt, $user) = split(/\s/,$_,2); next unless $dt and $user; push(@{$users{$user}}, $dt); } foreach my $user (keys %users) { printf( "%-20s : %s\n", $user, $DURATION->format_duration( spanset_from_list( @{$users{$user}} )->duration ) ); } sub spanset_from_list { return undef if @_ % 2; my @dates = @_; my @spans; for( my $i=0; $i < scalar(@dates); $i+=2 ) { push(@spans, DateTime::Span->new( start => $ISO->parse_datetime($dates[$i]), end => $ISO->parse_datetime($dates[$i+1]), )); } return DateTime::SpanSet->from_spans( spans => [EMAIL PROTECTED] ); } __DATA__ 2005-01-01T08:55 Mr Coffee 2005-01-01T08:58 BigLug 2005-01-01T12:01 BigLug 2005-01-01T13:01 BigLug 2005-01-01T17:23 Mr Coffee 2005-01-01T17:26 BigLug