The method I use is: subtract_datetime_absolute() method.
for example: $dt2 and $dt1 are 2 datetime objects with $dt2 greater than $dt1;
my $abs_duration = $dt2->subtract_datetime_absolute($dt1);
$abs_duration holds the number of seconds and nanoseconds between the 2 dates;
to convert to days I simply use this conversion.
my $days = $abs_duration->seconds / (60 * 60 * 24);
for date2 = 2005-05-14 and date1 = 2005-03-14, I get 62 days;
doing the standard way I get 2 months and 1 day
Below is a quote from perldoc datetime.
subtract_datetime_absolute( $datetime ) This method returns a new "DateTime::Duration" object representing the difference between the two dates. The duration object will only have deltas for seconds and nanoseconds. This is the only way to accurately measure the absolute amount of time between two datetimes, since units larger than a second do not represent a fixed number of seconds.
----- Original Message ----- From: "Dave Rolsky" <[EMAIL PROTECTED]>
To: "Kirrily Robert" <[EMAIL PROTECTED]>
Cc: <datetime@perl.org>
Sent: Tuesday, April 26, 2005 12:48 AM
Subject: Re: DateTime::Duration and days
On Tue, 26 Apr 2005, Kirrily Robert wrote:
I'm trying to use DateTime::Duration to show the difference in days, as an integer, between two dates. For instance, the difference between March 1st and April 2nd should be 32 days. Unfortunately if I use the math stuff in Datetime, I end up with a duration object which says one month and one day, and I can't for the life of me figure out how to make it do otherwise.
Is this possible, or am I trying to do something insane? What *should* I be doing?
There's a delta_days() method in the DateTime class which can be used to give you a duration with only days.
-dave
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