Hi All, I wrote a script with two cases. In the first case the set unites between the spans and in the second set it does not unite. Can you please explain me what is the difference and how in the first case I can bring them to unite ? (I am using version 0.25)
Best regards, David Here is the script ##################################### use strict; use warnings; use DateTime::SpanSet; my $a= DateTime->new(year=>1998); my $b = DateTime->new(year=>2002); my $c = DateTime->new(year=>2004); my $d = DateTime->new(year=>2005); my $e = DateTime->new(year=>1994); my $span1 = DateTime::Span->from_datetimes( start => $a, before => $b ); my $span2 = DateTime::Span->from_datetimes( start => $c, before => $d ); my $span3 = DateTime::Span->from_datetimes( start => $e, before => $c ); my $set1 = DateTime::SpanSet->from_spans(spans=>[$span1,$span2]); my $set2 = DateTime::SpanSet->from_spans(spans=>[$span3]); my $set3 = $set1->union($set2); my @list = $set3->as_list; print "running union between [1998,2002),[2004,2005),[1994,2004) gives the following result\n"; print $list[0]->start->ymd,"\t",$list[0]->end->ymd,"\n"; print $list[1]->start->ymd,"\t",$list[1]->end->ymd,"\n"; print "running union between [2002,2004),[2004,2005) gives the following result\n"; my $span4 = DateTime::Span->from_datetimes( start => $b, before => $c ); my $set4 = DateTime::SpanSet->from_spans(spans=>[$span4]); my $set5 = DateTime::SpanSet->from_spans(spans=>[$span2]); my $set6 = $set4->union($set5); my @list = $set6->as_list; print $list[0]->start->ymd,"\t",$list[0]->end->ymd,"\n"; ################################## And here is the output running union between [1998,2002),[2004,2005),[1994,2004) gives the following result 1994-01-01 2004-01-01 2004-01-01 2005-01-01 running union between [2002,2004),[2004,2005) gives the following result 2002-01-01 2005-01-01
