[email protected] wrote:
> +/* An ECC layout for using 4-bit ECC with large-page (2048bytes) flash,
> + * storing ten ECC bytes plus the manufacturer's bad block marker byte,
> + * and not overlapping the default BBT markers.
> + */
> +static struct nand_ecclayout hwecc4_2048 __initconst = {
> +     .eccbytes = 40,
> +     .eccpos = {
> +             /* at the end of spare sector */
> +             24, 25, 26, 27, 28, 29, 30, 31, 32, 33,
> +             34, 35, 36, 37, 38, 39, 40, 41, 42, 43,
> +             44, 45, 46, 47, 48, 49, 50, 51, 52, 53,
> +             54, 55, 56, 57, 58, 59, 60, 61, 62, 63,
> +             },
> +     .oobfree = {
> +             /* 1 byte at offset 0 holds manufacturer badblock marker */
> +             {.offset = 1, .length = 23, },
> +             /* 5 bytes at offset 8 hold BBT markers */
> +             /* 8 bytes at offset 16 hold JFFS2 clean markers */
> +     },
> +};

I hate to sound like a broken record, but

If the bad block marker is only 1 byte. Don't you need to override

static struct nand_bbt_descr largepage_flashbased = {
        .options = NAND_BBT_SCAN2NDPAGE,
        .offs = 0,
        .len = 2,
        .pattern = scan_ff_pattern
};

I think it is easier just to leave it as 2 bytes. That may
allow substituting a different manufacturers chip too.



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