Andy, *what* is that statement supposed to be doing?
Typically you
1. prepare the sql
2. execute the sql
This statement:
my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367'
}
or die "Can't prepare SQL statement:
",$ucscHandle->errstr(), "\n";
is neither. It In fact, the warning indicates that Perl thinks you are
trying to do a comparison. Where is the 'prepare' - where is the
'execute'?? All that statement does is set $sql equal to a string - the
die is meaningless.
Hardy Merrill
>>> Andy Hammer <[EMAIL PROTECTED]> 07/01/04 08:54PM >>>
I am getting the warning:
Found = in conditional, should be == at NM_000367.pl line 32.
line 32 contains my sql query:
my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367' }
or die "Can't prepare SQL statement:
",$ucscHandle->errstr(), "\n";
The query fuctions fine, but I am curious why I am getting that
warning...?
--
Andy Hammer
Gesteland / Atkins Lab
