On 1/4/07, Fernan Aguero <[EMAIL PROTECTED]> wrote:
+----[ Patrik Wallstrom <[EMAIL PROTECTED]> (04.Jan.2007 18:30):
| I really can't figure out how to do it from the artist/cd examples in
| cookbok. Subscription has not a direct relation with item.
but why then are you joining on feed_id? To me this looks
like a relation.
Basically its an implied relation. If foo has_many bar, and bar
has_many baz, then its implied that foo has_many baz. If you don't
use the implied/indirect relationship often, use the join syntax like
Fernan wrote for those one-off queries. If you'll probably use it a
lot, you could just define an has_many and/or belongs_to directly
between these tables.
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