On Wed, Jul 20, 2011 at 11:28 AM, Eden Cardim <[email protected]> wrote:
> This means that assigning to $_[0] modifies the scalar within the caller
> scope.

And because of "my ($obj) = @_;" and then modifying $obj instead of
modifying $_[0], it didn't work for me. Follow the recipe properly (!)
and the dish turns out delicious...

Thanks!
-- 
Peter Valdemar Mørch
http://www.morch.com

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